Acceleration due to gravity

surface of a massive body, such as a planet. Also known as the acceleration of free fall, its value can be calculated from the formula

g = GM / (R + h) 2

whereM is the mass of the gravitating body (such as the Earth), R is the radius of the body, h is the height above the surface, and G is the gravitational constant (= 6.6742 × 10-11 N·m2/kg2). If the falling object is at, or very nearly at, the surface of the gravitating body, then the above equation reduces to

g = GM / R 2

In the case of the Earth, g comes out to be approximately 9.8 m/s2(32 ft/s2), though the exact value depends on location because of two main factors: the Earth's rotation and the Earth's equatorial bulge.

The earth is not perfectly round, it is slightly egg-shaped, wider at the equator as it spins. The farther you are from the center of the earth the less gravity, the less you weigh. So if you are on a high mountain or at the equator you will weigh a teeny bit less. Your mass stays the same thought

Comments

Post a Comment

Popular posts from this blog

Softening point IS 1205 1978

Hot the bitumen in oven or on hot plate at 75oc – 110oc above softening point say at 90oc + softening point of bitumen and pour it in the rings Balls weights 3.5 gms and dia of Ball is 9.5 mm After 30 min in air place it in beaker 600 ml and keep it in apparatus the temp of Distilled water should be 0oc and heat it at the rate of 5oc /min place the thermometer and note down the temp when balls touched the lower plate. For CRMB 55 the Softening point is 55oc For CRMB 50 the softening point is 50oc And For CRMB 60 the Softening point is 60oc For Bitumen having the Softening point above 80oc use Glysrine in place of water and the starting temp should be 35oc In IS 1205 1978 the water bath is written to perfotm the test first keep the beaker with sample in water bath for 15 min at 5oc and then allow to rise the temp at 5oc per min.
Read more

Shear Strength of concrete

Concrete subjected to bending and and shear stress is accopanied by tensile and compressive stress. The shear failure are due to resulting diagonal tension. The shear strength is generally 12 to 13 percent of compressive strength.
Read more